Jump to content
  • 0

Party Nick Color


foti

Question

Recommended Posts

  • 0

Try this:
 

	public void joinParty(L2Party party)
	{
		if (party != null)
		{
			_party = party;
			party.addPartyMember(this);
+			this.getAppearance().setNameColor(nameColor);
		}
	}

L2PcInstance.java;line ~5269;aCis

Link to comment
Share on other sites

  • 0

Try this:

 

	public void joinParty(L2Party party)
	{
		if (party != null)
		{
			_party = party;
			party.addPartyMember(this);
+			this.getAppearance().setNameColor(nameColor);
		}
	}

L2PcInstance.java;line ~5269;aCis

 

thats shitty.

  • Others can see it
  • Its permanent
  • You dont handle party leave
  • not what he asked for
  • you dont need a null check as far as your pack is coded properly
Edited by xxdem
Link to comment
Share on other sites

  • 0

 

thats shitty.

  • Others can see it
  • Its permanent
  • You dont handle party leave
  • not what he asked for
  • you dont need a null check as far as your pack is coded properly

 

Yeah I forgot to remove party color,but shouldn't others see it?What is the point of it if you are the only one who can see it?

 

+	int orgColor;
	public void joinParty(L2Party party)
	{
		if (party != null)
		{
			_party = party;
			party.addPartyMember(this);
		}
+		orgColor = this.getAppearance().getNameColor();
+		this.getAppearance().setNameColor(nameColor);
		
	}

	/**
	 * Manage the Leave Party task of the L2PcInstance.
	 */
	public void leaveParty()
	{
		if (isInParty())
		{
			_party.removePartyMember(this);
			_party = null;
		}
+		this.getAppearance().setNameColor(orgColor);
	}

If this isn't what thread author wanted,then I am sorry for misunderstanding.

or like St3et said:

 

if(_activeChar.isInParty())
    writeD(color);
else
    writeD(_activeChar.getAppearance().getNameColor());
Edited by StealthyS4m
Link to comment
Share on other sites

  • 0

I doube that would change something. Since all party will have "same color". Else, you code it to give random color and store them, so another party won't take the same color.

Link to comment
Share on other sites

  • 0

You need to send different nameColor in CharInfo packet. There are 2 places where you can inject the code:

1. In constructor of CharInfo. In my sources i have forPlayer parameter.

2. writeImpl() method in CharInfo.java. You can get info to who the packet is sent(getClient().getActiveChar()).

 

The code itself should look something like this:

if(player.getParty() != null && player.getParty().equals(forPlayer.getParty())
	_nameColor = 0x666666;
else
	_nameColor = player.getVisibleNameColor();

Take in mind you most likely have different sources than mine, so the exact code will not work but the way of doing this feature will be the same.

Link to comment
Share on other sites

  • 0

You need to send different nameColor in CharInfo packet. There are 2 places where you can inject the code:

1. In constructor of CharInfo. In my sources i have forPlayer parameter.

2. writeImpl() method in CharInfo.java. You can get info to who the packet is sent(getClient().getActiveChar()).

 

The code itself should look something like this:

if(player.getParty() != null && player.getParty().equals(forPlayer.getParty())
	_nameColor = 0x666666;
else
	_nameColor = player.getVisibleNameColor();

Take in mind you most likely have different sources than mine, so the exact code will not work but the way of doing this feature will be the same.

 

getClient().getActiveChar() the dude that recieves

constructor parameter the guy who is broadcasted

Link to comment
Share on other sites

  • 0

and you know how much random colors you can work on l2 :P

 

I doube that would change something. Since all party will have "same color". Else, you code it to give random color and store them, so another party won't take the same color.

10 or more? :D

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Answer this question...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.



×
×
  • Create New...

AdBlock Extension Detected!

Our website is made possible by displaying online advertisements to our members.

Please disable AdBlock browser extension first, to be able to use our community.

I've Disabled AdBlock