Hello i have this qquest working properly tested more than 10 times.
But i am not sure why a player can take the quest again and again after completed.
I want the quest to be done only 1 time by a player.
/*
* This program is free software: you can redistribute it and/or modify it under
* the terms of the GNU General Public License as published by the Free Software
* Foundation, either version 3 of the License, or (at your option) any later version.
*
* This program is distributed in the hope that it will be useful, but WITHOUT
* ANY WARRANTY; without even the implied warranty of MERCHANTABILITY or FITNESS
* FOR A PARTICULAR PURPOSE. See the GNU General Public License for more details.
*
* You should have received a copy of the GNU General Public License along with
* this program. If not, see <http://www.gnu.org/licenses/>.
*/
package quests.Q701_PathOfNoblesseTwo;
import net.sf.l2j.gameserver.model.actor.L2Npc;
import net.sf.l2j.gameserver.model.actor.instance.L2PcInstance;
import net.sf.l2j.gameserver.model.quest.Quest;
import net.sf.l2j.gameserver.model.quest.QuestState;
public class Q701_PathOfNoblesseTwo extends Quest
{
private static final String qn = "Q701_PathOfNoblesseTwo";
// Item
private static final int GRAVE_ROBBERS_HEAD = 1474;
private static final int CARADINES_LETTER = 7678;
private static final int CARADINES_LETTER_1 = 7679;
public Q701_PathOfNoblesseTwo()
{
super(701, qn, "Path Of Noblesse Two");
setItemsIds(GRAVE_ROBBERS_HEAD);
addStartNpc(50011); // Exemia
addTalkId(50011);
addKillId(21353, 21354, 21355); // Varka Silenos Scout, Varka Silenos Hunter, Varka Silenos Shaman
}
@Override
public String onAdvEvent(String event, L2Npc npc, L2PcInstance player)
{
String htmltext = event;
QuestState st = player.getQuestState(qn);
if (st == null)
return htmltext;
if (event.equalsIgnoreCase("50011-03.htm"))
{
st.setState(STATE_STARTED);
st.set("cond", "1");
st.playSound(QuestState.SOUND_ACCEPT);
}
return htmltext;
}
@Override
public String onTalk(L2Npc npc, L2PcInstance player)
{
String htmltext = getNoQuestMsg();
QuestState st = player.getQuestState(qn);
if (st == null)
return htmltext;
switch (st.getState())
{
case STATE_CREATED:
if (player.getLevel() < 75)
htmltext = "50011-01.htm";
else
htmltext = "50011-02.htm";
break;
case STATE_STARTED:
if (st.getInt("cond") == 1)
htmltext = "50011-04.htm";
else
{
htmltext = "50011-05.htm";
st.takeItems(GRAVE_ROBBERS_HEAD, -1);
st.takeItems(CARADINES_LETTER, -1);
st.giveItems(CARADINES_LETTER_1, 1);
st.rewardItems(57, 3000000);
st.playSound(QuestState.SOUND_FINISH);
st.exitQuest(false);
}
break;
//I Add this 4 lines but still players can do it.
//Can someone correct it please?
case STATE_COMPLETED:
htmltext = getAlreadyCompletedMsg();
break;
}
return htmltext;
}
@Override
public String onKill(L2Npc npc, L2PcInstance player, boolean isPet)
{
QuestState st = checkPlayerCondition(player, npc, "cond", "1");
if (st == null)
return null;
if (st.dropItemsAlways(GRAVE_ROBBERS_HEAD, 1, 1000))
st.set("cond", "2");
return null;
}
public static void main(String[] args)
{
new Q701_PathOfNoblesseTwo();
}
}
You can post now and register later.
If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.
Original was based off L2OFF, so how would he even be able to compete or deliver the same quality? It will be just another L2F from shein.
Whatsoever, some times you should just let the horse die.
Bump
NEW USER IN TELEGRAM AND DISCORD IS "mileanum"
NEW USER IN TELEGRAM AND DISCORD IS "mileanum"
NEW USER IN TELEGRAM AND DISCORD IS "mileanum"
NEW USER IN TELEGRAM AND DISCORD IS "mileanum"
Question
killer666
Hello i have this qquest working properly tested more than 10 times.
But i am not sure why a player can take the quest again and again after completed.
I want the quest to be done only 1 time by a player.
6 answers to this question
Recommended Posts
Join the conversation
You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.