Jump to content

Recommended Posts

Posted

If you don't know what SQL injection is, all you need to know about it as it relates to your server's website is that a malicious user could use your own php scripts to modify your server's database or potentially even take full control of your MySQL database.

 

With the following scripts you can have better security..

 

(One word of caution: SQL Injection may still be possible if a user finds a way to pass a "change charset" command to your MySQL database. I can't think of a way to do that through any of these scripts, so they *should* be safe.)

 

Account registration:

 

PHP code:

<?php 
//set host, username and password for MySQL 
$dbhost = "localhost"; 
$dbuser = "YOURMYSQLUSERNAME"; 
$dbpass = "YOURMYSQLPASSWORD"; 
  
//connect to MySQL or return an error 
$conn = mysql_connect("$dbhost", "$dbuser", "$dbpass") 
or die('Could not connect: ' . mysql_error()); 
  
//set database name 
$dbname = "l2jdb"; 
  
//select database or return an error 
$dbselect = mysql_select_db("$dbname")  
or die ('Could not select database'); 
  
//get username and password info from the form, protecting against SQL injection 
$pass = mysql_real_escape_string($_POST["pass"]); 
$confirm = mysql_real_escape_string($_POST["confirm"]); 
$user = mysql_real_escape_string($_POST["name"]); 
  
//validate user input 
if(!preg_match('/^[a-zA-Z0-9]{5,20}$/',$user)) { 
die ('Error: Usernames can only contain alphanumeric characters and must be between 5 and 20 characters in length.'); 
} 
  
if(!preg_match('/^[a-zA-Z0-9]{5,20}$/',$pass)) { 
die ('Error: Passwords can only contain alphanumeric characters and must be between 5 and 20 characters in length.'); 
} 
  
if($pass != $confirm) { 
die ('Error: Passwords do not match.'); 
} 
  
//make sure user doesn't already exist and if it doesn't, add new record to the database 
$result = mysql_query("SELECT login FROM accounts WHERE login='$user'"); 
  
if(mysql_num_rows($result)>0) { 
die ('Error: Username already exists.'); 
}else{ 
mysql_query("INSERT INTO accounts (login, password, access_level) VALUES ('".$_POST['name']."', '".base64_encode(pack('H*', sha1($_POST['pass'])))."', 0)") 
or die ('Error: ' . mysql_error()); 
} 
  
//report successful registration 
echo "Account created successfully."; 
  
//close MySQL connection 
mysql_close(); 
  
?>

 

Save this as acc.php and then use the following html to add the account registration form to your webpage

 

<form action="acc.php" method=post>
UserID: <input type="text" name="name" size=20><br><br>
Password: <input type="password" name="pass" size=20><br><br>
Confirm Password: <input type="password" name="confirm" size=20><br><br>
<input type=submit name="submit" value="Create"></form>

 

The script has built in protection against SQL injection and also forces the user to submit a username and password that are between 5 and 20 characters in length, and limits them to only alphanumeric characters.

 

Password reset scripts are even more subject to SQL injection exploits, so here is a (to the best of my knowledge) secure password reset script.

 

<?php 
  
//set host, username and password for MySQL 
$dbhost = "localhost"; 
$dbuser = "YOURMYSQLUSERNAME"; 
$dbpass = "YOURMYSQLPASSWORD"; 
  
//connect to MySQL or return an error 
$conn = mysql_connect("$dbhost", "$dbuser", "$dbpass") 
or die('Could not connect: ' . mysql_error()); 
  
//set database name 
$dbname = "l2jdb"; 
  
//select database or return an error 
$dbselect = mysql_select_db("$dbname")  
or die ('Could not select database'); 
  
//get username and password info from the form, protecting against SQL injection 
$user = mysql_real_escape_string($_POST["name"]); 
$currentpass = mysql_real_escape_string($_POST["currentpass"]); 
$newpass = mysql_real_escape_string($_POST["newpass"]); 
$confirm = mysql_real_escape_string($_POST["confirm"]); 
  
//username and password should already be valid and newpass and confirm should match or this script will die 
//so just validate the newpass and then check to see if newpass and confirm are the same 
if(!preg_match('/^[a-zA-Z0-9]{5,20}$/',$newpass)) { 
die ('Error: Passwords can only contain alphanumeric characters and must be between 5 and 20 characters in length.'); 
} 
  
if($newpass != $confirm) { 
die ('Error: New passwords do not match.'); 
} 
  
//encrypt the passwords 
$currentpass = base64_encode(pack('H*', sha1($currentpass))); 
$newpass = base64_encode(pack('H*', sha1($newpass))); 
  
//if the user input passed all the checks, make sure the account exists and then update the password 
$result = mysql_query("SELECT login,password FROM accounts WHERE login='$user' AND password='$currentpass'"); 
  
if(mysql_num_rows($result)>0) { 
mysql_query("UPDATE accounts SET password='$newpass' WHERE login='$user' AND password='$currentpass'"); 
echo "Password succesfully updated.";  
}else{ 
die ('Error: Account does not exist or password is incorrect.'); 
} 
  
//close MySQL connection 
mysql_close(); 
  
?>

 

Save the preceding as changepass.php and use the following HTML to insert a change password form into your website.

 

<form action="changepass.php" method=post> UserID:<input type="text" name="name" size=20><br><br> Password: <input type="password" name="currentpass" size=20><br><br> New password: <input type="password" name="newpass" size=20><br><br> Confirm password:<input type="password" name="confirm" size=20><br><br> <input type=submit name="submit" value="Update Password"> 

 

This script uses the same protection as the registration script, and should be safe against all the SQL injection exploits that I can come up with.

 

Server status scripts don't take any input from the user, and thus are not susceptible to SQL injection, but here is a server status script that is tested and working, and as a bonus will use graphics to display your server status.

 

<?php 
  
//set server, port and timeout information 
$server = "localhost"; 
$portg = "7777"; 
$portl = "2106"; 
$timeout = "1"; 

//try to open a connection to the game and login server  
$game = @fsockopen("$server", $portg, $errno, $errstr, $timeout); 
$login = @fsockopen("$server", $portl, $errno, $errstr, $timeout); 
  
//let us know if the servers are up or not  
echo $game ? "<img src=\"gameonline.jpg\">" : "<img src=\"gameoffline.jpg\">"; 
echo $login ? "<img src=\"loginonline.jpg\">" : "<img src=\"loginoffline.jpg\">"; 
  
  
?>

 

All you have to do with this one is create a few graphics and insert the preceding php directly into your HTML whever you want the server status displayed. If the script isn't self-explanatory, the graphics you need to create are gameonline.jpg, gameoffline.jpg, loginonline.jpg and loginoffline.jpg.

 

And last but not least, here is a little script that will display the number of users currently online as a graphic on your webpage.

 

<?php 
  
//set host, username and password for MySQL 
$dbhost = "localhost"; 
$dbuser = "YOURMYSQLUSERNAME"; 
$dbpass = "YOURMYSQLPASSWORD"; 
  
//connect to MySQL or return an error 
$conn = mysql_connect("$dbhost", "$dbuser", "$dbpass") 
or die('Could not connect: ' . mysql_error()); 
  
//set database name 
$dbname = "l2jdb"; 
  
//select database or return an error 
$dbselect = mysql_select_db("$dbname") or die ('Could not select database'); 
  
//select all records from the characters table where that character is currently online 
$chars = mysql_query("SELECT online FROM characters where online='1'") or die ('Query failed: ' . mysql_error()); 
  
//count how many online characters there are 
$rows = mysql_num_rows($chars); 
  
//convert the number of online characters to a string 
$count =(string)$rows; 
  
//convert each digit in the string to a graphic 
for ($i=0; $i < strlen($count); $i++) { echo('<img src="' . $count{$i} . '.jpg">'); }  
  
//close MySQL connection 
mysql_close(); 
  
?>

 

Save this as onlineplayers.php and then insert the following code into your html where you want to display the number of online players.

 

<?php 
include 'onlineplayers.php'; 
?>

 

Now all you need to do is create a graphic for each digit and save them as 0.jpg, 1.jpg, 2.jpg, 3.jpg, 4.jpg, 5.jpg, 6.jpg, 7.jpg, 8.jpg, and 9.jpg. The script will find the number of players currently online and use the graphics you created to diplay the number on your page.

 

 

credits to:threadreaper

  • 1 month later...
Posted

All the PHP and HTML codes are [C O D E D]

 

do it the next time you will release an other guide with scripts.

 

bye.

  • 3 weeks later...
  • 4 months later...
  • 2 months later...
  • 2 weeks later...

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.

×
×
  • Create New...