L2Net is an in-game (IG) bot. I already have Adrenaline for that. I'm looking for an out-of-game (OOG) bot - one that doesn’t require the Lineage 2 client to run.
I came here to say something about ave but it seems i am late already
Note for people who might see this topic.
Use custom sources of updater, do it your self, learn do it on your time and schedule.
its only a how to build it in visual studio youtube video and you're done 90%
no time? pay to a pro like nevesoma.
its easy as fuck
Hello everyone, this is ADENA L2REBORN / LU4 / MASTERWORK
We also have items, epics, etc.
discord - adver745645
Our prices are reasonable, so have a nice shopping and a nice day.
Question
GsL
Kalimera mages
Kserei kaneis ti prepei na kanw wste na girizei piso sto spawn point ena L2Monster
otan pernaei ena X distance apo to spawn point tou?
To pack m einai l2jfrozen last revision
to pack exei ena config alla den work ...
dokimasa auto to code alla tipota
/** * Return home. */ public void returnHome() { ThreadPoolManager.getInstance().scheduleAi(new Runnable() { @Override public void run() { L2Spawn mobSpawn = getSpawn(); if(!isInCombat() && !isAlikeDead() && !isDead() && mobSpawn != null && !isInsideRadius(mobSpawn.getLocx(), mobSpawn.getLocy(), Config.MAX_DRIFT_RANGE, false)) { teleToLocation(mobSpawn.getLocx(), mobSpawn.getLocy(), mobSpawn.getLocz(), false); } mobSpawn = null; } }, 1000); } protected void startMaintenanceTask() { ThreadPoolManager.getInstance().scheduleGeneralAtFixedRate(new Runnable() { @Override public void run() { checkAndReturnToSpawn(); } }, 3000, getMaintenanceInterval()+Rnd.get(5000)); } protected void checkAndReturnToSpawn() { if (isDead() || isMovementDisabled()) return; final L2Spawn spawn = getSpawn(); if (spawn == null) return; final int spawnX = spawn.getLocx(); final int spawnY = spawn.getLocy(); final int spawnZ = spawn.getLocz(); if (!isInCombat() && !isMovementDisabled()) { if (!isInsideRadius(spawnX, spawnY, spawnZ, Math.max(1000, 200), true, false)) teleToLocation(spawnX, spawnY, spawnZ); } }4 answers to this question
Recommended Posts