WANTED13 Posted November 19, 2008 Author Posted November 19, 2008 Afou re file esi dineis tin lisi etoimi ... ;P nai dose kamia na liso exo oreksi :P
xXSkillerXx Posted November 19, 2008 Posted November 19, 2008 (x+α).(x+β) = ? Ela auti einai gia pro8ermansi. :P
Black Jack Posted November 19, 2008 Posted November 19, 2008 re c diakrinousa exei tipo β2-4*α*γ (*=Επι) -24 vgainei an eimai sostos... kai an eina ithetikos tote kanoume kai liseis x1 kai x2 an thimamai kala [EDIT] meta ap oafto p ithela na apadisw eginan 5 posts opote leave it for now...grafw arga eksiswseis se pc :P
Phoenix4 Posted November 19, 2008 Posted November 19, 2008 Test post να δοκιμάσο μια το χ2 Edit: ωραία έπιασε :P
WANTED13 Posted November 19, 2008 Author Posted November 19, 2008 kai ego afto skeftika! episis warning otan dinis apantisi dinis kai kai mia askisi :P pare mia lipn (p+1).(p+2)=? kai auti einai gia na kseskaseis :P
xXSkillerXx Posted November 19, 2008 Posted November 19, 2008 re c diakrinousa exei tipo β<2>-4*α*γ (*=Επι) -24 vgainei an eimai sostos... kai an eina ithetikos tote kanoume kai liseis x1 kai x2 an thimamai kala Από ότι 8υμάμαι ρε φίλε...όταν έχεις διακρίνουσα αρνητική, δεν παραγωντοποιείς. Αν είναι θετική τότε διακρίνεις περιπτώσεις ( για χ1,χ2) : χ1,χ2 = -β +/- (ρίζα Δ) ____________ 2.α Η κάπως έτσι! :P
WANTED13 Posted November 19, 2008 Author Posted November 19, 2008 otan apantas 8a dinis kai mia askisi!!!!!!!!!!!
Black Jack Posted November 19, 2008 Posted November 19, 2008 opos vlepeis Eipa...Kai An einai THETIKOS exoume liseis x1 kai x2 :D :D tespa spam topicx to kaname..sinexiste paides ta leme avrio...arketa diavaza prin dianismata ftanei gia apopse..Cya
xXSkillerXx Posted November 19, 2008 Posted November 19, 2008 otan apantas 8a dinis kai mia askisi!!!!!!!!!!! Nai kirie xD (p+1).(p+2) = p2+2p+p+2 = p2+3p+2 Tsiba ena trionimo! :P
Stealth Posted November 19, 2008 Posted November 19, 2008 Έχουμε και λέμε: β2 + 4αγ = 32 + 4*1*2 = 9 + 8 = 17 άρα 1η λύση -β +- (ρίζα) Δ -3 + (ρίζα) 17 3 + 4.12 7 χ =-------------- = --------------- = ---------------- =/ ---- 2*α 2*1 2 2 2η λύση -β +- (ρίζα) Δ -3 - (ρίζα) 17 3 - 17 15 χ =-------------- = --------------- = ---------------- =/ - ---- 2*α 2*1 2 2 Δεν ξέρω αν είναι σωστά... τέσπα... τα έκανα βιαστικά... Βάλτε κάτι σε φυσική που το κατέχω... :P Θα βάλω άσκηση πιό μετά...
Stealth Posted November 19, 2008 Posted November 19, 2008 Aν α=(-1,3) και β=(2,5) (ΣΗΜΕΙΩΣΗ:είναι διανύσματα)... Να βρείτε τα εσωτερικά γινόμενα : α*β , (2α)*(-3β) και (α-β)*(3α+β) και ο Θεός βοηθός.... :P Άντε ελάτε εύκολα είναι Μαθηματικά Β' Λυκείου Κατεύθυνση , Σελίδα 47 , Άσκησεις Α' Ομάδας , Άσκηση 1. :P
WANTED13 Posted November 21, 2008 Author Posted November 21, 2008 ipologizo kai 8a kanw edit se ligo ! esis sinexiste!
malakaso0 Posted November 21, 2008 Posted November 21, 2008 geia sas ekana pira auto to pexnidaki apo ena alo forum kai elpizo na exi epitixia kai edo!!! 8a lew Mia exisosi i tipota alo pollaplasiasmo i tpt tetio kai o epomenos 8a ti lini kai 8a leei mia ali o paraepomenos pou 8a pi 8a pi an einai sosti afti pou elise o alos elpizo na katalabate ! p.x: 1+1 o epomenos =2 kai sinexizi me mia dikia t lipon arxizo ego : 2 Epi(2x+1)=4x+2 epeidh kaneis den to katalabe, as to apanthso egw! 4x+2=0 -> 4x=-2 => x=-1/2 duskolo e? xD
naturalkillergr Posted November 21, 2008 Posted November 21, 2008 epeidh kaneis den to katalabe, as to apanthso egw! 4x+2=0 -> 4x=-2 => x=-1/2 duskolo e? xD Pff...Grapse esy allo :P TeCpA 2x+3=9(2x+3) Siga...Paneukolo re :P (Lusi : ipenthimizo +x+=+,-x-=+,-x+=-,+x-=- ...dn thelo sxolia xD... 2x+3=18x+27 2x-18x=-3+27 -16x=24 -16x:-16=24:-16 ...dn mporo na kano klasma :S x=24:16 siga... :P)
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