Philipe Posted October 31, 2008 Posted October 31, 2008 This is good for low rate servers: For enchant: 1- Press scroll to enchant 2- Drop the scroll but not confirme the drop 3- Put the window of enchant behind of window to confirm the drop where the two buttons "OK" stay one behind other. 4- Start to attack one NPC. 5- Press fast "OK" to drop scroll and "OK" to enchant. 6- You will see if enchant or broken, and u can calculate the chances of sucess
--Shady-- Posted October 31, 2008 Posted October 31, 2008 where you test that? client interlude or kamel hellbound grica?
Live Posted October 31, 2008 Posted October 31, 2008 well i will test this one, if it's working i will edit my post and tell what's happen.
Hybrid Posted October 31, 2008 Posted October 31, 2008 i dont understand this, when i broken my weapon i have only scrol and crystals from weapon?
Philipe Posted October 31, 2008 Author Posted October 31, 2008 Its only simuling, this work for me in Interlude. You will recive one message if broken or was suceful, but nothing will happen with your weapon because the scroll will be dropped. When the weapon broken 3-5 times, you enchant your weapon and the chances to get suceful will be greatly. Its not 100%, depending how you do, but I arealy do weapons +12 with this in server 14x.
GrisoM Posted October 31, 2008 Posted October 31, 2008 Well the onlything that give me any hope of this to work is the same line where u say: 3- Put the window of enchant behind of window to confirm the drop where the two buttons "OK" stay one behind other. Beacuse whit this step i find the dupe exploit for adena ^^ Lets try and i report here back later.-
savasLT Posted November 1, 2008 Posted November 1, 2008 GUYS!!!LineAge II DON'T HAVE ANY ******* ENCHANT BUG!...It is JUST LUCK!!! :|
woen Posted November 1, 2008 Posted November 1, 2008 GUYS!!!LineAge II DON'T HAVE ANY ******* ENCHANT BUG!...It is JUST LUCK!!! :| First, Lineage 2 have enchant bug in Interlude version, the famous warehouse enchant, and second, it's very usefull for calculate the succes rate :) Thx and sorrry for my english.
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