Jump to content

[Help] V.B. 2008


avatar

Recommended Posts

Ok i've got the code bellow for "Visual Basic 2008" but i want it to generate numbers from a list ".txt" ex. "NumberList.txt" "1, 2, 3, 4 - ,999999"

I dont want it to randomize nmbers !

Public Class Form1

    Private Sub Button4_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button4.Click
        Timer1.Start()
    End Sub

    Private Sub Button5_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button5.Click
        Timer1.Stop()
    End Sub

    Private Sub Timer2_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer2.Tick

    End Sub

    Private Sub Button1_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button1.Click
        Timer1.Interval = ("5000")
    End Sub

    Private Sub Button2_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button2.Click
        Timer1.Interval = ("2500")
    End Sub

    Private Sub Button3_Click(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Button3.Click
        Timer1.Interval = ("1500")
    End Sub

    Private Sub Timer1_Tick(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles Timer1.Tick
        SendKeys.Send(Int(Val(TextBox1.Text) * Rnd()))
        SendKeys.Send("{enter}")
    End Sub

    Private Sub Form1_Load(ByVal sender As System.Object, ByVal e As System.EventArgs) Handles MyBase.Load

    End Sub
End Class

Link to comment
Share on other sites

You mean you want it to read a .txt file with numbers?

Lets say the txt file contains this:

1
2
3
4
5
6

 

You want your program to read those numbers and post them line by line in a textbox or listbox?

Link to comment
Share on other sites

for generating random numbers use RND (example: rnd() * 50000, output will be between 0 and 50000)

 

and for +1 all the time just use a simple loop for that (i just know it for C++,,, dont know atm for vb lol but you maybe will get my point :P)

 

for(unsigned int i = 0; i < 50000; i++)

{

//Here the numbers will go +1 till 50000

//out put will be:

// 0

// 1

// 2

// 3

// 4

//.....

}

Link to comment
Share on other sites

for generating random numbers use RND (example: rnd() * 50000, output will be between 0 and 50000)

 

Yeah only this could generate real numbers too. (I got 33553.37 as random number)

The way to do it properly for integers is this:

Dim minimum_number As Integer = 1
       Dim maximum_number As Integer = 10
       Dim random_number As New Random
       MsgBox(random_number.Next(minimum_number, maximum_number))

or for a random number between 1 and 10 could be done easier

       Dim random_number As New Random
       MsgBox(random_number.Next(1, 10))

or for a function:

Function GenerateRandomNumber(ByVal minimum_number As Integer, ByVal maximum_number As Integer) As Integer
       Dim rnd As New Random : Return rnd.Next(minimum_number, maximum_number)
End Function

 

 

Link to comment
Share on other sites

i dont want random numbers !! i want 1 to 9999999 but thx for help

You mean this?

For i = 1 to 9999999
'Do something here
next i

Link to comment
Share on other sites

Join the conversation

You can post now and register later. If you have an account, sign in now to post with your account.
Note: Your post will require moderator approval before it will be visible.

Guest
Reply to this topic...

×   Pasted as rich text.   Paste as plain text instead

  Only 75 emoji are allowed.

×   Your link has been automatically embedded.   Display as a link instead

×   Your previous content has been restored.   Clear editor

×   You cannot paste images directly. Upload or insert images from URL.



×
×
  • Create New...

AdBlock Extension Detected!

Our website is made possible by displaying online advertisements to our members.

Please disable AdBlock browser extension first, to be able to use our community.

I've Disabled AdBlock