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Posted

With that i know, in theory it must work....

 

i cant find problem ... but it dosent work, my program end even size is  > 4

 

# include <iostream>

using namespace std;

void main() {
  
  int Year;
  int xSize;

  cin >> Year; // Example we put 2011 
  xSize = sizeof(Year); // Size of Year / Size of 2011 is 4

  // While size is > 4 then loop ...
  while (xSize > 4){
 
           cout << "GTFO Man, limit is 4 numbers.... Again Year...";
           cin >> Year;
 }

}

 

 

PS: Dont tell me use <1 & >9999, i dont want this way.

Posted

if you put, for eg 12212 at year.. it will show you that the size is 4 :|

 

my english is not so good, anyway that i want is limit of numbers max 4 numbers as year, dont want put year example 12345

 

BTW im using wrong way i think, sizeof(_val); i think means the size of bytes....

 

 

ahaha :(... again from 0 ... loking for answer...How can. ...

Posted

I told you... either this way:

if((year>=0)&&(year>=9999))
{
   //code
}
else
   cout <<"GTFO!"endl;

 

or my other post ;)

here:

 

#include <iostream>
#include <sstream>
using namespace std;

int main()
{
bool succ;
int intYear;
string strYear;
cout <<"Value for strYear:";
cin >> strYear;
if(strYear.length()<=4)
{
	stringstream sti(strYear);
	sti >> 	intYear;   //this should be two lines lower but there's a problem with the if...nvm it works like this too
	if(intYear==0)
	{
		cout<<"Wrong year input...use numbers!"<<endl;
		succ=0;
	}
	else
	{
		cout<<"strYear is <= 4 digits, converting it to integer in variable intYear..."<<endl;
		succ=1;
	}
}
else
{
	cout<<"Wrong year input.(must be < 9999)"<<endl;
	succ=0;
}

if(succ==1)
{
	//code
}
else
{
	cout <<"exiting program..."<<endl;
}
return 0;
}

Posted

Hax0r i know those 2 ways...

i dont want using <1 >9999

 

i dont want create a string and put value of int on it... using lenght()

 

just with 1 way ;ppp

... anyway bcause professor say who find it wil take +1 bonus

 

his question was simple

 

how can print only 4 numbers using cout

 

exmaple if we put 123456789 cout wil print only 1234

 

well i hope i find it before 18:00 and i take bonus xD

 

and if not np ...

 

my english  sux ;p

Posted

Did the professor give you the right answer?

meanwhile I thought of this :P

 

#include <iostream>
using namespace std;

int main()
{
int year;
do{
	cin >>year; //has to be >0
}while(year-9999>=1);
        //code
return 0;
}

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